Base | Representation |
---|---|
bin | 100111011101100… |
… | …1000000000000000 |
3 | 10102021120101001201 |
4 | 1032323020000000 |
5 | 10202433401422 |
6 | 335220310544 |
7 | 44545565215 |
oct | 11673100000 |
9 | 3367511051 |
10 | 1324122112 |
11 | 61a4835a5 |
12 | 30b542454 |
13 | 181432711 |
14 | c7bddb0c |
15 | 7b3a7727 |
hex | 4eec8000 |
1324122112 has 64 divisors (see below), whose sum is σ = 2805160140. Its totient is φ = 622854144.
The previous prime is 1324122083. The next prime is 1324122119. The reversal of 1324122112 is 2112214231.
It can be written as a sum of positive squares in 2 ways, for example, as 1312178176 + 11943936 = 36224^2 + 3456^2 .
It is a tau number, because it is divible by the number of its divisors (64).
It is a self number, because there is not a number n which added to its sum of digits gives 1324122112.
It is not an unprimeable number, because it can be changed into a prime (1324122119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 555868 + ... + 558244.
Almost surely, 21324122112 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1324122112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1402580070).
1324122112 is an abundant number, since it is smaller than the sum of its proper divisors (1481038028).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1324122112 is an frugal number, since it uses more digits than its factorization.
1324122112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2424 (or 2396 counting only the distinct ones).
The product of its digits is 192, while the sum is 19.
The square root of 1324122112 is about 36388.4887292671. The cubic root of 1324122112 is about 1098.1019919569.
Adding to 1324122112 its reverse (2112214231), we get a palindrome (3436336343).
It can be divided in two parts, 13241 and 22112, that added together give a palindrome (35353).
The spelling of 1324122112 in words is "one billion, three hundred twenty-four million, one hundred twenty-two thousand, one hundred twelve".
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