Base | Representation |
---|---|
bin | 11110000110111001001101… |
… | …000011101100011111110000 |
3 | 122100211202121101202022022121 |
4 | 132012321031003230133300 |
5 | 114323442143421100000 |
6 | 1145342401213044024 |
7 | 36614451321521161 |
oct | 3606711503543760 |
9 | 570752541668277 |
10 | 132415134550000 |
11 | 39211a41441875 |
12 | 12a26b34786614 |
13 | 58b6902b23403 |
14 | 249acd8c5b768 |
15 | 104964c9b0b1a |
hex | 786e4d0ec7f0 |
132415134550000 has 120 divisors (see below), whose sum is σ = 323510202115632. Its totient is φ = 52497325440000.
The previous prime is 132415134549983. The next prime is 132415134550001. The reversal of 132415134550000 is 55431514231.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132415134550001) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6068154 + ... + 17368153.
Almost surely, 2132415134550000 is an apocalyptic number.
132415134550000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132415134550000 is an abundant number, since it is smaller than the sum of its proper divisors (191095067565632).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132415134550000 is an equidigital number, since it uses as much as digits as its factorization.
132415134550000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23436453 (or 23436427 counting only the distinct ones).
The product of its (nonzero) digits is 36000, while the sum is 34.
The spelling of 132415134550000 in words is "one hundred thirty-two trillion, four hundred fifteen billion, one hundred thirty-four million, five hundred fifty thousand".
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