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132421352519 is a prime number
BaseRepresentation
bin111101101010011101…
…1010111110001000111
3110122210200010200211202
41323110323113301013
54132144331240034
6140500013053115
712365344632101
oct1732473276107
9418720120752
10132421352519
1151183446115
12217b778719b
13c6447283c1
1465a2cc6571
1536a070647e
hex1ed4ed7c47

132421352519 has 2 divisors, whose sum is σ = 132421352520. Its totient is φ = 132421352518.

The previous prime is 132421352471. The next prime is 132421352521. The reversal of 132421352519 is 915253124231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132421352519 - 220 = 132420303943 is a prime.

It is a super-3 number, since 3×1324213525193 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 132421352521, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132421352419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66210676259 + 66210676260.

It is an arithmetic number, because the mean of its divisors is an integer number (66210676260).

Almost surely, 2132421352519 is an apocalyptic number.

132421352519 is a deficient number, since it is larger than the sum of its proper divisors (1).

132421352519 is an equidigital number, since it uses as much as digits as its factorization.

132421352519 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 64800, while the sum is 38.

The spelling of 132421352519 in words is "one hundred thirty-two billion, four hundred twenty-one million, three hundred fifty-two thousand, five hundred nineteen".