Base | Representation |
---|---|
bin | 1100000010110110011001… |
… | …1001000111100010111110 |
3 | 1201220000202112212102002121 |
4 | 3000231212121013202332 |
5 | 3213433333110042420 |
6 | 44055444100513154 |
7 | 2534532261655414 |
oct | 300554631074276 |
9 | 51800675772077 |
10 | 13243102034110 |
11 | 4246405940093 |
12 | 159a7280ab7ba |
13 | 750a85917990 |
14 | 33ad8067b2b4 |
15 | 17e73bade2aa |
hex | c0b666478be |
13243102034110 has 64 divisors (see below), whose sum is σ = 26747006920704. Its totient is φ = 4687801833600.
The previous prime is 13243102034081. The next prime is 13243102034143. The reversal of 13243102034110 is 1143020134231.
13243102034110 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14924536 + ... + 15786955.
It is an arithmetic number, because the mean of its divisors is an integer number (417921983136).
Almost surely, 213243102034110 is an apocalyptic number.
13243102034110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13243102034110 is an abundant number, since it is smaller than the sum of its proper divisors (13503904886594).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13243102034110 is a wasteful number, since it uses less digits than its factorization.
13243102034110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30711649.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13243102034110 its reverse (1143020134231), we get a palindrome (14386122168341).
The spelling of 13243102034110 in words is "thirteen trillion, two hundred forty-three billion, one hundred two million, thirty-four thousand, one hundred ten".
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