13243719413 has 2 divisors, whose sum is σ = 13243719414. Its totient is φ = 13243719412.

The previous prime is 13243719407. The next prime is 13243719451. The reversal of 13243719413 is 31491734231.

It is an a-pointer prime, because the next prime (13243719451) can be obtained adding 13243719413 to its sum of digits (38).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12087243364 + 1156476049 = 109942^2 + 34007^2 .

It is a cyclic number.

It is not a de Polignac number, because 13243719413 - 2¹⁴ = 13243703029 is a prime.

It is a super-3 number, since 3×13243719413³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13243719613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6621859706 + 6621859707.

It is an arithmetic number, because the mean of its divisors is an integer number (6621859707).

Almost surely, 2^13243719413 is an apocalyptic number.

It is an amenable number.

13243719413 is a deficient number, since it is larger than the sum of its proper divisors (1).

13243719413 is an equidigital number, since it uses as much as digits as its factorization.

13243719413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 54432, while the sum is 38.

The spelling of 13243719413 in words is "thirteen billion, two hundred forty-three million, seven hundred nineteen thousand, four hundred thirteen".