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132443342231 is a prime number
BaseRepresentation
bin111101101011000111…
…1010000010110010111
3110122212012111220001112
41323112033100112113
54132220443422411
6140502120245235
712366032556044
oct1732617202627
9418765456045
10132443342231
11511948a5332
122180301081b
13c649157375
1465a5bac1cb
1536a25ebb8b
hex1ed63d0597

132443342231 has 2 divisors, whose sum is σ = 132443342232. Its totient is φ = 132443342230.

The previous prime is 132443342183. The next prime is 132443342233. The reversal of 132443342231 is 132243344231.

It is a strong prime.

It is an emirp because it is prime and its reverse (132243344231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132443342231 - 210 = 132443341207 is a prime.

It is a super-2 number, since 2×1324433422312 (a number of 23 digits) contains 22 as substring.

Together with 132443342233, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132443342233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66221671115 + 66221671116.

It is an arithmetic number, because the mean of its divisors is an integer number (66221671116).

Almost surely, 2132443342231 is an apocalyptic number.

132443342231 is a deficient number, since it is larger than the sum of its proper divisors (1).

132443342231 is an equidigital number, since it uses as much as digits as its factorization.

132443342231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 32.

Adding to 132443342231 its reverse (132243344231), we get a palindrome (264686686462).

The spelling of 132443342231 in words is "one hundred thirty-two billion, four hundred forty-three million, three hundred forty-two thousand, two hundred thirty-one".