Base | Representation |
---|---|
bin | 111101101011001000… |
… | …1110001100011110110 |
3 | 110122212020202102211210 |
4 | 1323112101301203312 |
5 | 4132221131040200 |
6 | 140502142342250 |
7 | 12366041306136 |
oct | 1732621614366 |
9 | 418766672753 |
10 | 132444002550 |
11 | 51195206452 |
12 | 2180328a986 |
13 | c649328aa2 |
14 | 65a5d00ac6 |
15 | 36a26cc650 |
hex | 1ed64718f6 |
132444002550 has 48 divisors (see below), whose sum is σ = 328485493440. Its totient is φ = 35315780640.
The previous prime is 132444002531. The next prime is 132444002573. The reversal of 132444002550 is 55200444231.
It is a super-2 number, since 2×1324440025502 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2823589 + ... + 2870111.
It is an arithmetic number, because the mean of its divisors is an integer number (6843447780).
Almost surely, 2132444002550 is an apocalyptic number.
132444002550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132444002550 is an abundant number, since it is smaller than the sum of its proper divisors (196041490890).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132444002550 is a wasteful number, since it uses less digits than its factorization.
132444002550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65517 (or 65512 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 30.
Adding to 132444002550 its reverse (55200444231), we get a palindrome (187644446781).
The spelling of 132444002550 in words is "one hundred thirty-two billion, four hundred forty-four million, two thousand, five hundred fifty".
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