Base | Representation |
---|---|
bin | 1100000011000111000000… |
… | …1010101111100011000010 |
3 | 1201220110021022012121120212 |
4 | 3000301300022233203002 |
5 | 3214022001104132000 |
6 | 44101502344034122 |
7 | 2535050624414315 |
oct | 300616012574302 |
9 | 51813238177525 |
10 | 13247561005250 |
11 | 4248293908100 |
12 | 159b571462942 |
13 | 751316657540 |
14 | 33b28494697c |
15 | 17e8ed2c5c35 |
hex | c0c702af8c2 |
13247561005250 has 96 divisors (see below), whose sum is σ = 29355720187248. Its totient is φ = 4446733632000.
The previous prime is 13247561005229. The next prime is 13247561005373. The reversal of 13247561005250 is 5250016574231.
It can be written as a sum of positive squares in 8 ways, for example, as 1749405667801 + 11498155337449 = 1322651^2 + 3390893^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13247561005198 and 13247561005207.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 16450439 + ... + 17236938.
Almost surely, 213247561005250 is an apocalyptic number.
13247561005250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13247561005250 is an abundant number, since it is smaller than the sum of its proper divisors (16108159181998).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13247561005250 is a wasteful number, since it uses less digits than its factorization.
13247561005250 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33687429 (or 33687408 counting only the distinct ones).
The product of its (nonzero) digits is 252000, while the sum is 41.
Adding to 13247561005250 its reverse (5250016574231), we get a palindrome (18497577579481).
The spelling of 13247561005250 in words is "thirteen trillion, two hundred forty-seven billion, five hundred sixty-one million, five thousand, two hundred fifty".
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