Base | Representation |
---|---|
bin | 11110001000001000101001… |
… | …001001000101101011010000 |
3 | 122101010220202212200200111121 |
4 | 132020020221021011223100 |
5 | 114331341340410030000 |
6 | 1145445505143052024 |
7 | 36623561131266106 |
oct | 3610105111055320 |
9 | 571126685620447 |
10 | 132500431330000 |
11 | 39245132230088 |
12 | 12a3b57a441014 |
13 | 58c1977428076 |
14 | 24a10ab26dc76 |
15 | 104b990eaab1a |
hex | 788229245ad0 |
132500431330000 has 100 divisors (see below), whose sum is σ = 321283603586880. Its totient is φ = 52919744752000.
The previous prime is 132500431329991. The next prime is 132500431330063. The reversal of 132500431330000 is 33134005231.
It is a tau number, because it is divible by the number of its divisors (100).
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 3463144 + ... + 16643143.
Almost surely, 2132500431330000 is an apocalyptic number.
132500431330000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132500431330000 is an abundant number, since it is smaller than the sum of its proper divisors (188783172256880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132500431330000 is an equidigital number, since it uses as much as digits as its factorization.
132500431330000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20106974 (or 20106953 counting only the distinct ones).
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 132500431330000 its reverse (33134005231), we get a palindrome (132533565335231).
The spelling of 132500431330000 in words is "one hundred thirty-two trillion, five hundred billion, four hundred thirty-one million, three hundred thirty thousand".
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