Base | Representation |
---|---|
bin | 11110010001000010100000… |
… | …000100101010100101111111 |
3 | 122110022102010220011002020202 |
4 | 132101002200010222211333 |
5 | 114421403003333441411 |
6 | 1151034541341434115 |
7 | 40016022116302313 |
oct | 3621024004524577 |
9 | 573272126132222 |
10 | 133112312015231 |
11 | 394606839a12aa |
12 | 12b1a083b6b93b |
13 | 593758b5a3023 |
14 | 24c2955353b43 |
15 | 105c853d7b83b |
hex | 7910a012a97f |
133112312015231 has 2 divisors, whose sum is σ = 133112312015232. Its totient is φ = 133112312015230.
The previous prime is 133112312015173. The next prime is 133112312015233. The reversal of 133112312015231 is 132510213211331.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (132510213211331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133112312015231 - 226 = 133112244906367 is a prime.
It is a super-2 number, since 2×1331123120152312 (a number of 29 digits) contains 22 as substring.
Together with 133112312015233, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 133112312015194 and 133112312015203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133112312015233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556156007615 + 66556156007616.
It is an arithmetic number, because the mean of its divisors is an integer number (66556156007616).
Almost surely, 2133112312015231 is an apocalyptic number.
133112312015231 is a deficient number, since it is larger than the sum of its proper divisors (1).
133112312015231 is an equidigital number, since it uses as much as digits as its factorization.
133112312015231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 29.
Adding to 133112312015231 its reverse (132510213211331), we get a palindrome (265622525226562).
The spelling of 133112312015231 in words is "one hundred thirty-three trillion, one hundred twelve billion, three hundred twelve million, fifteen thousand, two hundred thirty-one".
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