Base | Representation |
---|---|
bin | 1100000011011111110010… |
… | …0000001011010000010100 |
3 | 1201221002102201012221011122 |
4 | 3000313330200023100110 |
5 | 3214124110330320200 |
6 | 44104522235423112 |
7 | 2535404455352531 |
oct | 300677440132024 |
9 | 51832381187148 |
10 | 13254210401300 |
11 | 4250096264840 |
12 | 15a09082b4a98 |
13 | 751b3612540b |
14 | 33b715ab9d88 |
15 | 17eb8be37385 |
hex | c0dfc80b414 |
13254210401300 has 36 divisors (see below), whose sum is σ = 31376330807136. Its totient is φ = 4819712872800.
The previous prime is 13254210401297. The next prime is 13254210401321. The reversal of 13254210401300 is 310401245231.
It is a happy number.
It is a self number, because there is not a number n which added to its sum of digits gives 13254210401300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6024639992 + ... + 6024642191.
Almost surely, 213254210401300 is an apocalyptic number.
13254210401300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13254210401300 is an abundant number, since it is smaller than the sum of its proper divisors (18122120405836).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13254210401300 is a wasteful number, since it uses less digits than its factorization.
13254210401300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12049282208 (or 12049282201 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 13254210401300 its reverse (310401245231), we get a palindrome (13564611646531).
The spelling of 13254210401300 in words is "thirteen trillion, two hundred fifty-four billion, two hundred ten million, four hundred one thousand, three hundred".
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