13255441050 has 24 divisors (see below), whose sum is σ = 32873494176. Its totient is φ = 3534784240.

The previous prime is 13255441039. The next prime is 13255441057. The reversal of 13255441050 is 5014455231.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 13255440999 and 13255441017.

It is not an unprimeable number, because it can be changed into a prime (13255441057) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 44184654 + ... + 44184953.

It is an arithmetic number, because the mean of its divisors is an integer number (1369728924).

Almost surely, 2^13255441050 is an apocalyptic number.

13255441050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13255441050 is an abundant number, since it is smaller than the sum of its proper divisors (19618053126).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13255441050 is a wasteful number, since it uses less digits than its factorization.

13255441050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 88369622 (or 88369617 counting only the distinct ones).

The product of its (nonzero) digits is 12000, while the sum is 30.

Adding to 13255441050 its reverse (5014455231), we get a palindrome (18269896281).

The spelling of 13255441050 in words is "thirteen billion, two hundred fifty-five million, four hundred forty-one thousand, fifty".