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13261326437 is a prime number
BaseRepresentation
bin11000101100110111…
…11100100001100101
31021020012112011221102
430112123330201211
5204124344421222
610031524125445
7646425262202
oct142633744145
937205464842
1013261326437
115695744917
1226a1236885
13133457b928
148db352ca9
15529371d92
hex3166fc865

13261326437 has 2 divisors, whose sum is σ = 13261326438. Its totient is φ = 13261326436.

The previous prime is 13261326433. The next prime is 13261326439. The reversal of 13261326437 is 73462316231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11553240196 + 1708086241 = 107486^2 + 41329^2 .

It is an emirp because it is prime and its reverse (73462316231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13261326437 - 22 = 13261326433 is a prime.

It is a super-2 number, since 2×132613264372 (a number of 21 digits) contains 22 as substring.

Together with 13261326439, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13261326437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13261326433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6630663218 + 6630663219.

It is an arithmetic number, because the mean of its divisors is an integer number (6630663219).

Almost surely, 213261326437 is an apocalyptic number.

It is an amenable number.

13261326437 is a deficient number, since it is larger than the sum of its proper divisors (1).

13261326437 is an equidigital number, since it uses as much as digits as its factorization.

13261326437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 108864, while the sum is 38.

The spelling of 13261326437 in words is "thirteen billion, two hundred sixty-one million, three hundred twenty-six thousand, four hundred thirty-seven".