Base | Representation |
---|---|
bin | 11110001010010111001110… |
… | …001011010100110110100010 |
3 | 122101200112221011120202010121 |
4 | 132022113032023110312202 |
5 | 114341343404121344300 |
6 | 1150044104310350454 |
7 | 36640620662520220 |
oct | 3612271613246642 |
9 | 571615834522117 |
10 | 132653524012450 |
11 | 392a4053042341 |
12 | 12a6518495b42a |
13 | 590323463c92c |
14 | 24a8671671b10 |
15 | 105095133a81a |
hex | 78a5ce2d4da2 |
132653524012450 has 96 divisors (see below), whose sum is σ = 282747629564928. Its totient is φ = 45358082568000.
The previous prime is 132653524012403. The next prime is 132653524012483. The reversal of 132653524012450 is 54210425356231.
It is a junction number, because it is equal to n+sod(n) for n = 132653524012397 and 132653524012406.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 260704785 + ... + 261213115.
It is an arithmetic number, because the mean of its divisors is an integer number (2945287807968).
Almost surely, 2132653524012450 is an apocalyptic number.
132653524012450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132653524012450 is an abundant number, since it is smaller than the sum of its proper divisors (150094105552478).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132653524012450 is a wasteful number, since it uses less digits than its factorization.
132653524012450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 510368 (or 510363 counting only the distinct ones).
The product of its (nonzero) digits is 864000, while the sum is 43.
Adding to 132653524012450 its reverse (54210425356231), we get a palindrome (186863949368681).
The spelling of 132653524012450 in words is "one hundred thirty-two trillion, six hundred fifty-three billion, five hundred twenty-four million, twelve thousand, four hundred fifty".
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