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132654144236597 is a prime number
BaseRepresentation
bin11110001010010111110011…
…001001010010110000110101
3122101200121112101122101201022
4132022113303021102300311
5114341401141411032342
61150044250024110525
736640642233400664
oct3612276311226065
9571617471571638
10132654144236597
11392a4341153985
1212a65318605445
135903302c99979
1424a86cdba0ddb
15105098aa009d2
hex78a5f3252c35

132654144236597 has 2 divisors, whose sum is σ = 132654144236598. Its totient is φ = 132654144236596.

The previous prime is 132654144236563. The next prime is 132654144236599. The reversal of 132654144236597 is 795632441456231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 116815328236996 + 15838815999601 = 10808114^2 + 3979801^2 .

It is a cyclic number.

It is not a de Polignac number, because 132654144236597 - 216 = 132654144171061 is a prime.

Together with 132654144236599, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132654144236599) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66327072118298 + 66327072118299.

It is an arithmetic number, because the mean of its divisors is an integer number (66327072118299).

Almost surely, 2132654144236597 is an apocalyptic number.

It is an amenable number.

132654144236597 is a deficient number, since it is larger than the sum of its proper divisors (1).

132654144236597 is an equidigital number, since it uses as much as digits as its factorization.

132654144236597 is an evil number, because the sum of its binary digits is even.

The product of its digits is 130636800, while the sum is 62.

The spelling of 132654144236597 in words is "one hundred thirty-two trillion, six hundred fifty-four billion, one hundred forty-four million, two hundred thirty-six thousand, five hundred ninety-seven".