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132732452351 is a prime number
BaseRepresentation
bin111101110011101111…
…0000111110111111111
3110200121100112012120202
41323213132013313333
54133314001433401
6140550525034115
712406143141512
oct1734736076777
9420540465522
10132732452351
1151323011014
12218839b593b
13c694011545
1465d2348d79
1536bcba906b
hex1ee7787dff

132732452351 has 2 divisors, whose sum is σ = 132732452352. Its totient is φ = 132732452350.

The previous prime is 132732452299. The next prime is 132732452353. The reversal of 132732452351 is 153254237231.

It is a strong prime.

It is an emirp because it is prime and its reverse (153254237231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132732452351 - 218 = 132732190207 is a prime.

It is a super-2 number, since 2×1327324523512 (a number of 23 digits) contains 22 as substring.

Together with 132732452353, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132732452353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66366226175 + 66366226176.

It is an arithmetic number, because the mean of its divisors is an integer number (66366226176).

Almost surely, 2132732452351 is an apocalyptic number.

132732452351 is a deficient number, since it is larger than the sum of its proper divisors (1).

132732452351 is an equidigital number, since it uses as much as digits as its factorization.

132732452351 is an evil number, because the sum of its binary digits is even.

The product of its digits is 151200, while the sum is 38.

Adding to 132732452351 its reverse (153254237231), we get a palindrome (285986689582).

The spelling of 132732452351 in words is "one hundred thirty-two billion, seven hundred thirty-two million, four hundred fifty-two thousand, three hundred fifty-one".