Base | Representation |
---|---|
bin | 11000101111101100… |
… | …01110010110111111 |
3 | 1021021212001112121022 |
4 | 30113312032112333 |
5 | 204201424224242 |
6 | 10034131254355 |
7 | 650133400256 |
oct | 142766162677 |
9 | 37255045538 |
10 | 13284992447 |
11 | 56a8039501 |
12 | 26a914a3bb |
13 | 133944689c |
14 | 90055379d |
15 | 52b4990d2 |
hex | 317d8e5bf |
13284992447 has 2 divisors, whose sum is σ = 13284992448. Its totient is φ = 13284992446.
The previous prime is 13284992389. The next prime is 13284992449. The reversal of 13284992447 is 74429948231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13284992447 - 224 = 13268215231 is a prime.
Together with 13284992449, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13284992449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6642496223 + 6642496224.
It is an arithmetic number, because the mean of its divisors is an integer number (6642496224).
Almost surely, 213284992447 is an apocalyptic number.
13284992447 is a deficient number, since it is larger than the sum of its proper divisors (1).
13284992447 is an equidigital number, since it uses as much as digits as its factorization.
13284992447 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3483648, while the sum is 53.
The spelling of 13284992447 in words is "thirteen billion, two hundred eighty-four million, nine hundred ninety-two thousand, four hundred forty-seven".
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