Base | Representation |
---|---|
bin | 1111110110011… |
… | …11001010110111 |
3 | 100021012112101002 |
4 | 13323033022313 |
5 | 233020003033 |
6 | 21105553515 |
7 | 3203135066 |
oct | 773171267 |
9 | 307175332 |
10 | 132969143 |
11 | 6906a75a |
12 | 3864589b |
13 | 21718088 |
14 | 139341dd |
15 | ba183e8 |
hex | 7ecf2b7 |
132969143 has 2 divisors, whose sum is σ = 132969144. Its totient is φ = 132969142.
The previous prime is 132969119. The next prime is 132969167. The reversal of 132969143 is 341969231.
It is a balanced prime because it is at equal distance from previous prime (132969119) and next prime (132969167).
It is an emirp because it is prime and its reverse (341969231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132969143 - 226 = 65860279 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 132969097 and 132969106.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132969643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66484571 + 66484572.
It is an arithmetic number, because the mean of its divisors is an integer number (66484572).
Almost surely, 2132969143 is an apocalyptic number.
132969143 is a deficient number, since it is larger than the sum of its proper divisors (1).
132969143 is an equidigital number, since it uses as much as digits as its factorization.
132969143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 34992, while the sum is 38.
The square root of 132969143 is about 11531.2246964492. The cubic root of 132969143 is about 510.4073933094.
The spelling of 132969143 in words is "one hundred thirty-two million, nine hundred sixty-nine thousand, one hundred forty-three".
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