Base | Representation |
---|---|
bin | 10011010110101010110… |
… | …101110101101001001011 |
3 | 11201010222202121001022121 |
4 | 103112222311311221023 |
5 | 133242330322301124 |
6 | 2454555414232111 |
7 | 165042626053423 |
oct | 23265265655113 |
9 | 4633882531277 |
10 | 1330011134539 |
11 | 47306668081a |
12 | 195922055637 |
13 | 9855b88a609 |
14 | 48531291483 |
15 | 248e39ed2e4 |
hex | 135aad75a4b |
1330011134539 has 2 divisors, whose sum is σ = 1330011134540. Its totient is φ = 1330011134538.
The previous prime is 1330011134537. The next prime is 1330011134567. The reversal of 1330011134539 is 9354311100331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1330011134539 - 21 = 1330011134537 is a prime.
Together with 1330011134537, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1330011134537) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665005567269 + 665005567270.
It is an arithmetic number, because the mean of its divisors is an integer number (665005567270).
Almost surely, 21330011134539 is an apocalyptic number.
1330011134539 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330011134539 is an equidigital number, since it uses as much as digits as its factorization.
1330011134539 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14580, while the sum is 34.
The spelling of 1330011134539 in words is "one trillion, three hundred thirty billion, eleven million, one hundred thirty-four thousand, five hundred thirty-nine".
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