1330011134537 has 2 divisors, whose sum is σ = 1330011134538. Its totient is φ = 1330011134536.

The previous prime is 1330011134519. The next prime is 1330011134539. The reversal of 1330011134537 is 7354311100331.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1297448571136 + 32562563401 = 1139056^2 + 180451^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330011134537 - 2²⁸ = 1329742699081 is a prime.

Together with 1330011134539, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1330011134539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665005567268 + 665005567269.

It is an arithmetic number, because the mean of its divisors is an integer number (665005567269).

Almost surely, 2^{1330011134537} is an apocalyptic number.

It is an amenable number.

1330011134537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330011134537 is an equidigital number, since it uses as much as digits as its factorization.

1330011134537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11340, while the sum is 32.

Adding to 1330011134537 its reverse (7354311100331), we get a palindrome (8684322234868).

The spelling of 1330011134537 in words is "one trillion, three hundred thirty billion, eleven million, one hundred thirty-four thousand, five hundred thirty-seven".