Base | Representation |
---|---|
bin | 111101111011101111… |
… | …1001001011101011000 |
3 | 110201022002010210022001 |
4 | 1323313133021131120 |
5 | 4134341244001230 |
6 | 141033324210344 |
7 | 12415615114405 |
oct | 1736737113530 |
9 | 421262123261 |
10 | 133001156440 |
11 | 5145075a409 |
12 | 219399999b4 |
13 | c7078a2549 |
14 | 6619cd32ac |
15 | 36d65850ca |
hex | 1ef77c9758 |
133001156440 has 32 divisors (see below), whose sum is σ = 299311206480. Its totient is φ = 53190044032.
The previous prime is 133001156437. The next prime is 133001156441. The reversal of 133001156440 is 44651100331.
It is a super-2 number, since 2×1330011564402 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133001156399 and 133001156408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133001156441) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 117127 + ... + 528886.
Almost surely, 2133001156440 is an apocalyptic number.
133001156440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133001156440 is an abundant number, since it is smaller than the sum of its proper divisors (166310050040).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133001156440 is a wasteful number, since it uses less digits than its factorization.
133001156440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 651171 (or 651167 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 133001156440 its reverse (44651100331), we get a palindrome (177652256771).
The spelling of 133001156440 in words is "one hundred thirty-three billion, one million, one hundred fifty-six thousand, four hundred forty".
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