Base | Representation |
---|---|
bin | 11110001111011011001001… |
… | …101100010110010011011000 |
3 | 122102220210201010212020021001 |
4 | 132033123021230112103120 |
5 | 114413043221312242130 |
6 | 1150511550030354344 |
7 | 40005013135336411 |
oct | 3617331154262330 |
9 | 572823633766231 |
10 | 133001341134040 |
11 | 39418608806845 |
12 | 12b0067405b9b4 |
13 | 5929c84bc2b12 |
14 | 24bb429242808 |
15 | 1059a0b9056ca |
hex | 78f6c9b164d8 |
133001341134040 has 64 divisors (see below), whose sum is σ = 306344322315360. Its totient is φ = 51949374597120.
The previous prime is 133001341134029. The next prime is 133001341134043. The reversal of 133001341134040 is 40431143100331.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133001341134043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 148217329 + ... + 149111968.
Almost surely, 2133001341134040 is an apocalyptic number.
133001341134040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133001341134040 is an abundant number, since it is smaller than the sum of its proper divisors (173342981181320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133001341134040 is a wasteful number, since it uses less digits than its factorization.
133001341134040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 297329572 (or 297329568 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 133001341134040 its reverse (40431143100331), we get a palindrome (173432484234371).
The spelling of 133001341134040 in words is "one hundred thirty-three trillion, one billion, three hundred forty-one million, one hundred thirty-four thousand, forty".
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