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1330021212334 = 21739118270951
BaseRepresentation
bin10011010110101011011…
…100010010000010101110
311201011000110120001110021
4103112223130102002232
5133242340412243314
62455000414232354
7165043110525643
oct23265334220256
94634013501407
101330021212334
11473071334381
121959254b56ba
13985609a86c9
1448532755dca
15248e483e324
hex135ab7120ae

1330021212334 has 8 divisors (see below), whose sum is σ = 2112386631408. Its totient is φ = 625892335200.

The previous prime is 1330021212323. The next prime is 1330021212433. The reversal of 1330021212334 is 4332121200331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13300212123342 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1330021212299 and 1330021212308.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19559135442 + ... + 19559135509.

It is an arithmetic number, because the mean of its divisors is an integer number (264048328926).

Almost surely, 21330021212334 is an apocalyptic number.

1330021212334 is a deficient number, since it is larger than the sum of its proper divisors (782365419074).

1330021212334 is a wasteful number, since it uses less digits than its factorization.

1330021212334 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39118270970.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1330021212334 its reverse (4332121200331), we get a palindrome (5662142412665).

The spelling of 1330021212334 in words is "one trillion, three hundred thirty billion, twenty-one million, two hundred twelve thousand, three hundred thirty-four".

Divisors: 1 2 17 34 39118270951 78236541902 665010606167 1330021212334