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1330021220224 = 2710390790783
BaseRepresentation
bin10011010110101011011…
…100010011111110000000
311201011000110120110021111
4103112223130103332000
5133242340413021344
62455000414333104
7165043110560644
oct23265334237600
94634013513244
101330021220224
1147307133a2a4
121959254ba194
13985609ac188
1448532758c24
15248e4841834
hex135ab713f80

1330021220224 has 16 divisors (see below), whose sum is σ = 2649651649920. Its totient is φ = 665010610048.

The previous prime is 1330021220183. The next prime is 1330021220249. The reversal of 1330021220224 is 4220221200331.

It is a tau number, because it is divible by the number of its divisors (16).

It is a super-2 number, since 2×13300212202242 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1330021220195 and 1330021220204.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5195395264 + ... + 5195395519.

It is an arithmetic number, because the mean of its divisors is an integer number (165603228120).

Almost surely, 21330021220224 is an apocalyptic number.

It is an amenable number.

1330021220224 is a deficient number, since it is larger than the sum of its proper divisors (1319630429696).

1330021220224 is an equidigital number, since it uses as much as digits as its factorization.

1330021220224 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10390790797 (or 10390790785 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 1330021220224 its reverse (4220221200331), we get a palindrome (5550242420555).

The spelling of 1330021220224 in words is "one trillion, three hundred thirty billion, twenty-one million, two hundred twenty thousand, two hundred twenty-four".

Divisors: 1 2 4 8 16 32 64 128 10390790783 20781581566 41563163132 83126326264 166252652528 332505305056 665010610112 1330021220224