133004352040 has 32 divisors (see below), whose sum is σ = 342011191680. Its totient is φ = 45601492032.

The previous prime is 133004352037. The next prime is 133004352071. The reversal of 133004352040 is 40253400331.

It is a junction number, because it is equal to n+sod(n) for n = 133004351996 and 133004352014.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 237507492 + ... + 237508051.

It is an arithmetic number, because the mean of its divisors is an integer number (10687849740).

Almost surely, 2^133004352040 is an apocalyptic number.

133004352040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

133004352040 is an abundant number, since it is smaller than the sum of its proper divisors (209006839640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133004352040 is a wasteful number, since it uses less digits than its factorization.

133004352040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 475015561 (or 475015557 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 133004352040 its reverse (40253400331), we get a palindrome (173257752371).

The spelling of 133004352040 in words is "one hundred thirty-three billion, four million, three hundred fifty-two thousand, forty".