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1330110231269 is a prime number
BaseRepresentation
bin10011010110110000101…
…111110111001011100101
311201011020200001200110212
4103112300233313023211
5133243031204400034
62455013314225205
7165045241264241
oct23266057671345
94634220050425
101330110231269
11473107605646
1219594b285205
1398576275c31
14485404c9421
15248ec5752ce
hex135b0bf72e5

1330110231269 has 2 divisors, whose sum is σ = 1330110231270. Its totient is φ = 1330110231268.

The previous prime is 1330110231187. The next prime is 1330110231271. The reversal of 1330110231269 is 9621320110331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 715631402500 + 614478828769 = 845950^2 + 783887^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330110231269 - 28 = 1330110231013 is a prime.

It is a super-2 number, since 2×13301102312692 (a number of 25 digits) contains 22 as substring.

Together with 1330110231271, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1330110231169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665055115634 + 665055115635.

It is an arithmetic number, because the mean of its divisors is an integer number (665055115635).

Almost surely, 21330110231269 is an apocalyptic number.

It is an amenable number.

1330110231269 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330110231269 is an equidigital number, since it uses as much as digits as its factorization.

1330110231269 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 32.

The spelling of 1330110231269 in words is "one trillion, three hundred thirty billion, one hundred ten million, two hundred thirty-one thousand, two hundred sixty-nine".