Base | Representation |
---|---|
bin | 11110001111100101011101… |
… | …101000100011100000110010 |
3 | 122102221212021202201111011021 |
4 | 132033211131220203200302 |
5 | 114413233410223232010 |
6 | 1150521020425210054 |
7 | 40005554410453642 |
oct | 3617453550434062 |
9 | 572855252644137 |
10 | 133012413102130 |
11 | 3942227a62a2a1 |
12 | 12b0284403092a |
13 | 592b02a9c7a23 |
14 | 24bbb998c8522 |
15 | 1059e5895d8da |
hex | 78f95da23832 |
133012413102130 has 64 divisors (see below), whose sum is σ = 243819144576000. Its totient is φ = 52231333489920.
The previous prime is 133012413102109. The next prime is 133012413102137. The reversal of 133012413102130 is 31201314210331.
It is a junction number, because it is equal to n+sod(n) for n = 133012413102095 and 133012413102104.
It is not an unprimeable number, because it can be changed into a prime (133012413102137) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1255977921 + ... + 1256083819.
It is an arithmetic number, because the mean of its divisors is an integer number (3809674134000).
Almost surely, 2133012413102130 is an apocalyptic number.
133012413102130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133012413102130 is a deficient number, since it is larger than the sum of its proper divisors (110806731473870).
133012413102130 is a wasteful number, since it uses less digits than its factorization.
133012413102130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 109939.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 133012413102130 its reverse (31201314210331), we get a palindrome (164213727312461).
The spelling of 133012413102130 in words is "one hundred thirty-three trillion, twelve billion, four hundred thirteen million, one hundred two thousand, one hundred thirty".
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