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133031411124431 is a prime number
BaseRepresentation
bin11110001111110111001010…
…000000010000100011001111
3122110000200022202212000101212
4132033313022000100203033
5114414041312221440211
61150533441522525035
740010126245132031
oct3617671200204317
9573020282760355
10133031411124431
113942a339504676
1212b0646650677b
13592ca67922241
1424bca7caa9c51
15105a6bb75738b
hex78fdca0108cf

133031411124431 has 2 divisors, whose sum is σ = 133031411124432. Its totient is φ = 133031411124430.

The previous prime is 133031411124419. The next prime is 133031411124481. The reversal of 133031411124431 is 134421114130331.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 133031411124431 - 210 = 133031411123407 is a prime.

It is a super-2 number, since 2×1330314111244312 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133031411124481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66515705562215 + 66515705562216.

It is an arithmetic number, because the mean of its divisors is an integer number (66515705562216).

Almost surely, 2133031411124431 is an apocalyptic number.

133031411124431 is a deficient number, since it is larger than the sum of its proper divisors (1).

133031411124431 is an equidigital number, since it uses as much as digits as its factorization.

133031411124431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 32.

Adding to 133031411124431 its reverse (134421114130331), we get a palindrome (267452525254762).

The spelling of 133031411124431 in words is "one hundred thirty-three trillion, thirty-one billion, four hundred eleven million, one hundred twenty-four thousand, four hundred thirty-one".