Base | Representation |
---|---|
bin | 11110001111111000000111… |
… | …100100110011010001101110 |
3 | 122110000202222202121022201220 |
4 | 132033320013210303101232 |
5 | 114414100421143122110 |
6 | 1150534132223244210 |
7 | 40010163660322356 |
oct | 3617700744632156 |
9 | 573022882538656 |
10 | 133032444114030 |
11 | 3942a81960aa8a |
12 | 12b066b4449666 |
13 | 592cba09400a6 |
14 | 24bcb39d63b66 |
15 | 105a72c2a3370 |
hex | 78fe0793346e |
133032444114030 has 32 divisors (see below), whose sum is σ = 319331499405984. Its totient is φ = 35469359149056.
The previous prime is 133032444114013. The next prime is 133032444114043. The reversal of 133032444114030 is 30411444230331.
It is a junction number, because it is equal to n+sod(n) for n = 133032444113982 and 133032444114000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 372273519 + ... + 372630698.
It is an arithmetic number, because the mean of its divisors is an integer number (9979109356437).
Almost surely, 2133032444114030 is an apocalyptic number.
133032444114030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133032444114030 is an abundant number, since it is smaller than the sum of its proper divisors (186299055291954).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133032444114030 is a wasteful number, since it uses less digits than its factorization.
133032444114030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 744910180.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 133032444114030 its reverse (30411444230331), we get a palindrome (163443888344361).
The spelling of 133032444114030 in words is "one hundred thirty-three trillion, thirty-two billion, four hundred forty-four million, one hundred fourteen thousand, thirty".
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