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13307748653 is a prime number
BaseRepresentation
bin11000110010011010…
…00010000100101101
31021100102212200020202
430121031002010231
5204223240424103
610040303123245
7650530666013
oct143115020455
937312780222
1013307748653
115709971591
1226b48a3525
1313410836b4
149035988b3
1552d491988
hex31934212d

13307748653 has 2 divisors, whose sum is σ = 13307748654. Its totient is φ = 13307748652.

The previous prime is 13307748647. The next prime is 13307748659. The reversal of 13307748653 is 35684770331.

It is a balanced prime because it is at equal distance from previous prime (13307748647) and next prime (13307748659).

It can be written as a sum of positive squares in only one way, i.e., 9651490564 + 3656258089 = 98242^2 + 60467^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13307748653 is a prime.

It is a super-2 number, since 2×133077486532 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13307748598 and 13307748607.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13307748659) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6653874326 + 6653874327.

It is an arithmetic number, because the mean of its divisors is an integer number (6653874327).

Almost surely, 213307748653 is an apocalyptic number.

It is an amenable number.

13307748653 is a deficient number, since it is larger than the sum of its proper divisors (1).

13307748653 is an equidigital number, since it uses as much as digits as its factorization.

13307748653 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1270080, while the sum is 47.

The spelling of 13307748653 in words is "thirteen billion, three hundred seven million, seven hundred forty-eight thousand, six hundred fifty-three".