Search a number
-
+
1331000000000 = 2959113
BaseRepresentation
bin10011010111100101110…
…010000011111000000000
311201020112200022121201022
4103113211302003320000
5133301342000000000
62455241501125012
7165106264221206
oct23274562037000
94636480277638
101331000000000
1147352388a000
12195b59259768
13986886c96c8
14485c6741076
1524950730585
hex135e5c83e00

1331000000000 has 400 divisors, whose sum is σ = 3656425406832. Its totient is φ = 484000000000.

The previous prime is 1330999999997. The next prime is 1331000000009. The reversal of 1331000000000 is 1331.

The cubic root of 1331000000000 is 11000.

It is a perfect power (a cube), and thus also a powerful number.

It is a tau number, because it is divible by the number of its divisors (400).

It is a super-2 number, since 2×13310000000002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (8).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331000000009) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 120999999995 + ... + 121000000005.

Almost surely, 21331000000000 is an apocalyptic number.

1331000000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1331000000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1828212703416).

1331000000000 is an abundant number, since it is smaller than the sum of its proper divisors (2325425406832).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1331000000000 is an frugal number, since it uses more digits than its factorization.

1331000000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96 (or 18 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 8.

Adding to 1331000000000 its reverse (1331), we get a palindrome (1331000001331).

1331000000000 divided by its reverse (1331) gives a 9-th power (1000000000 = 109).

It can be divided in two parts, 13 and 31000000000, that added together give a palindrome (31000000013).

The spelling of 1331000000000 in words is "one trillion, three hundred thirty-one billion", and thus it is an aban number.