Base | Representation |
---|---|
bin | 10011010111100101111… |
… | …010111000100110011111 |
3 | 11201020112211200010201101 |
4 | 103113211322320212133 |
5 | 133301343043004434 |
6 | 2455242022453531 |
7 | 165106322664043 |
oct | 23274572704637 |
9 | 4636484603641 |
10 | 1331002313119 |
11 | 473525119976 |
12 | 195b59b942a7 |
13 | 9868902950b |
14 | 485c6b84023 |
15 | 24950a3ab14 |
hex | 135e5eb899f |
1331002313119 has 2 divisors, whose sum is σ = 1331002313120. Its totient is φ = 1331002313118.
The previous prime is 1331002313117. The next prime is 1331002313141. The reversal of 1331002313119 is 9113132001331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1331002313119 - 21 = 1331002313117 is a prime.
It is a super-2 number, since 2×13310023131192 (a number of 25 digits) contains 22 as substring.
Together with 1331002313117, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331002313117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665501156559 + 665501156560.
It is an arithmetic number, because the mean of its divisors is an integer number (665501156560).
Almost surely, 21331002313119 is an apocalyptic number.
1331002313119 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331002313119 is an equidigital number, since it uses as much as digits as its factorization.
1331002313119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 28.
The spelling of 1331002313119 in words is "one trillion, three hundred thirty-one billion, two million, three hundred thirteen thousand, one hundred nineteen".
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