1331002313141 has 2 divisors, whose sum is σ = 1331002313142. Its totient is φ = 1331002313140.

The previous prime is 1331002313119. The next prime is 1331002313143. The reversal of 1331002313141 is 1413132001331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1174522732516 + 156479580625 = 1083754^2 + 395575^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1331002313141 is a prime.

Together with 1331002313143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1331002313143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665501156570 + 665501156571.

It is an arithmetic number, because the mean of its divisors is an integer number (665501156571).

Almost surely, 2^{1331002313141} is an apocalyptic number.

It is an amenable number.

1331002313141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331002313141 is an equidigital number, since it uses as much as digits as its factorization.

1331002313141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1331002313141 its reverse (1413132001331), we get a palindrome (2744134314472).

The spelling of 1331002313141 in words is "one trillion, three hundred thirty-one billion, two million, three hundred thirteen thousand, one hundred forty-one".