Base | Representation |
---|---|
bin | 11110010000110111011010… |
… | …011100111000011101101100 |
3 | 122110021021102011220021200212 |
4 | 132100313122130320131230 |
5 | 114421204113033241030 |
6 | 1151025252130041552 |
7 | 40015121103365354 |
oct | 3620673234703554 |
9 | 573237364807625 |
10 | 133100406540140 |
11 | 39456624631696 |
12 | 12b17900a192b8 |
13 | 5936411bb5c00 |
14 | 24c21460ddb64 |
15 | 105c3a8a7d595 |
hex | 790dda73876c |
133100406540140 has 72 divisors (see below), whose sum is σ = 306496809743040. Its totient is φ = 48522679755264.
The previous prime is 133100406540119. The next prime is 133100406540151. The reversal of 133100406540140 is 41045604001331.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 133100406540097 and 133100406540106.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 248966009 + ... + 249500048.
It is an arithmetic number, because the mean of its divisors is an integer number (4256900135320).
Almost surely, 2133100406540140 is an apocalyptic number.
133100406540140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133100406540140 is an abundant number, since it is smaller than the sum of its proper divisors (173396403202900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133100406540140 is a wasteful number, since it uses less digits than its factorization.
133100406540140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 498466171 (or 498466156 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 32.
The spelling of 133100406540140 in words is "one hundred thirty-three trillion, one hundred billion, four hundred six million, five hundred forty thousand, one hundred forty".
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