Base | Representation |
---|---|
bin | 1100000110110011101101… |
… | …1001111011001100101000 |
3 | 1202010112021110121022220100 |
4 | 3001230323121323030220 |
5 | 3221042113134131440 |
6 | 44151011323425400 |
7 | 2542460321500635 |
oct | 301547331731450 |
9 | 52115243538810 |
10 | 13311100302120 |
11 | 427222a1122a5 |
12 | 15ab944685260 |
13 | 75730142c81a |
14 | 3403914a718c |
15 | 1813bb5e9230 |
hex | c1b3b67b328 |
13311100302120 has 96 divisors (see below), whose sum is σ = 43433431161120. Its totient is φ = 3535484784000.
The previous prime is 13311100302109. The next prime is 13311100302169. The reversal of 13311100302120 is 2120300111331.
13311100302120 is a `hidden beast` number, since 1 + 331 + 1 + 10 + 0 + 302 + 1 + 20 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 13311100302093 and 13311100302102.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 73565574 + ... + 73746293.
It is an arithmetic number, because the mean of its divisors is an integer number (452431574595).
Almost surely, 213311100302120 is an apocalyptic number.
13311100302120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13311100302120 is an abundant number, since it is smaller than the sum of its proper divisors (30122330859000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13311100302120 is a wasteful number, since it uses less digits than its factorization.
13311100302120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 147312135 (or 147312128 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 13311100302120 its reverse (2120300111331), we get a palindrome (15431400413451).
The spelling of 13311100302120 in words is "thirteen trillion, three hundred eleven billion, one hundred million, three hundred two thousand, one hundred twenty".
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