Base | Representation |
---|---|
bin | 1100000110110100001000… |
… | …0101100101100001111000 |
3 | 1202010112120021120001101002 |
4 | 3001231002011211201320 |
5 | 3221042330334123000 |
6 | 44151030410344132 |
7 | 2542463152424660 |
oct | 301550205454170 |
9 | 52115507501332 |
10 | 13311212411000 |
11 | 4272287424369 |
12 | 15ab97612b048 |
13 | 75731b722a3a |
14 | 3403a232b1a0 |
15 | 1813c63918d5 |
hex | c1b42165878 |
13311212411000 has 128 divisors (see below), whose sum is σ = 35750770623360. Its totient is φ = 4544256384000.
The previous prime is 13311212410973. The next prime is 13311212411041. The reversal of 13311212411000 is 11421211331.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2449691 + ... + 5711690.
It is an arithmetic number, because the mean of its divisors is an integer number (279302895495).
Almost surely, 213311212411000 is an apocalyptic number.
13311212411000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13311212411000 is an abundant number, since it is smaller than the sum of its proper divisors (22439558212360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13311212411000 is a wasteful number, since it uses less digits than its factorization.
13311212411000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8161642 (or 8161628 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 13311212411000 its reverse (11421211331), we get a palindrome (13322633622331).
The spelling of 13311212411000 in words is "thirteen trillion, three hundred eleven billion, two hundred twelve million, four hundred eleven thousand".
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