13311313003540 has 24 divisors (see below), whose sum is σ = 28347472202112. Its totient is φ = 5249531888160.

The previous prime is 13311313003531. The next prime is 13311313003567. The reversal of 13311313003540 is 4530031311331.

It is a junction number, because it is equal to n+sod(n) for n = 13311313003499 and 13311313003508.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4687080624 + ... + 4687083463.

It is an arithmetic number, because the mean of its divisors is an integer number (1181144675088).

Almost surely, 2^{13311313003540} is an apocalyptic number.

13311313003540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13311313003540 is an abundant number, since it is smaller than the sum of its proper divisors (15036159198572).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311313003540 is a wasteful number, since it uses less digits than its factorization.

13311313003540 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9374164167 (or 9374164165 counting only the distinct ones).

The product of its (nonzero) digits is 4860, while the sum is 28.

Adding to 13311313003540 its reverse (4530031311331), we get a palindrome (17841344314871).

The spelling of 13311313003540 in words is "thirteen trillion, three hundred eleven billion, three hundred thirteen million, three thousand, five hundred forty".