Base | Representation |
---|---|
bin | 1100000110110111000100… |
… | …0110001111110100111000 |
3 | 1202010121121020122021200002 |
4 | 3001231301012033310320 |
5 | 3221100434241112100 |
6 | 44151240543132132 |
7 | 2542521540325613 |
oct | 301556106176470 |
9 | 52117536567602 |
10 | 13312001113400 |
11 | 4272651649130 |
12 | 15abb562a4048 |
13 | 757415c4b552 |
14 | 340438d9517a |
15 | 1814207362d5 |
hex | c1b7118fd38 |
13312001113400 has 96 divisors (see below), whose sum is σ = 33768630611280. Its totient is φ = 4840074624000.
The previous prime is 13312001113387. The next prime is 13312001113679. The reversal of 13312001113400 is 431110021331.
13312001113400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 16053782 + ... + 16862618.
Almost surely, 213312001113400 is an apocalyptic number.
13312001113400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13312001113400 is an abundant number, since it is smaller than the sum of its proper divisors (20456629497880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13312001113400 is a wasteful number, since it uses less digits than its factorization.
13312001113400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 816345 (or 816336 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 13312001113400 its reverse (431110021331), we get a palindrome (13743111134731).
The spelling of 13312001113400 in words is "thirteen trillion, three hundred twelve billion, one million, one hundred thirteen thousand, four hundred".
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