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13312211234112 = 2632724719015279
BaseRepresentation
bin1100000110110111110110…
…0111110010110101000000
31202010122010220000112002200
43001231331213302311000
53221101402033442422
644151313450513200
72542530001324500
oct301557547626500
952118126015080
1013312211234112
11427274a213a0a
1215abbb4735800
1375744a63a32b
14340458c4da00
15181433dde2ac
hexc1b7d9f2d40

13312211234112 has 504 divisors, whose sum is σ = 45363609308160. Its totient is φ = 3719900620800.

The previous prime is 13312211234099. The next prime is 13312211234143. The reversal of 13312211234112 is 21143211221331.

13312211234112 is a `hidden beast` number, since 1 + 3 + 3 + 1 + 221 + 1 + 23 + 411 + 2 = 666.

It is a tau number, because it is divible by the number of its divisors (504).

It is a nude number because it is divisible by every one of its digits.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 2521727089 + ... + 2521732367.

Almost surely, 213312211234112 is an apocalyptic number.

13312211234112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13312211234112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22681804654080).

13312211234112 is an abundant number, since it is smaller than the sum of its proper divisors (32051398074048).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13312211234112 is a wasteful number, since it uses less digits than its factorization.

13312211234112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7259 (or 7239 counting only the distinct ones).

The product of its digits is 1728, while the sum is 27.

Adding to 13312211234112 its reverse (21143211221331), we get a palindrome (34455422455443).

The spelling of 13312211234112 in words is "thirteen trillion, three hundred twelve billion, two hundred eleven million, two hundred thirty-four thousand, one hundred twelve".