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13312213301549 is a prime number
BaseRepresentation
bin1100000110110111110110…
…1111101011100100101101
31202010122011000220120002102
43001231331233223210231
53221101403101122144
644151314003104445
72542530025025141
oct301557557534455
952118130816072
1013312213301549
1142727503a6238
1215abbb5372125
1375744abb2376
1434045922b221
1518143419bb4e
hexc1b7dbeb92d

13312213301549 has 2 divisors, whose sum is σ = 13312213301550. Its totient is φ = 13312213301548.

The previous prime is 13312213301381. The next prime is 13312213301551. The reversal of 13312213301549 is 94510331221331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8041024348900 + 5271188952649 = 2835670^2 + 2295907^2 .

It is a cyclic number.

It is not a de Polignac number, because 13312213301549 - 216 = 13312213236013 is a prime.

Together with 13312213301551, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13312213300549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656106650774 + 6656106650775.

It is an arithmetic number, because the mean of its divisors is an integer number (6656106650775).

Almost surely, 213312213301549 is an apocalyptic number.

It is an amenable number.

13312213301549 is a deficient number, since it is larger than the sum of its proper divisors (1).

13312213301549 is an equidigital number, since it uses as much as digits as its factorization.

13312213301549 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 58320, while the sum is 38.

The spelling of 13312213301549 in words is "thirteen trillion, three hundred twelve billion, two hundred thirteen million, three hundred one thousand, five hundred forty-nine".