Base | Representation |
---|---|
bin | 10011010111110111110… |
… | …010100001010001001111 |
3 | 11201021022201210102010012 |
4 | 103113313302201101033 |
5 | 133303001320012122 |
6 | 2455331452303435 |
7 | 165116623140212 |
oct | 23276762412117 |
9 | 4637281712105 |
10 | 1331302110287 |
11 | 473669374a26 |
12 | 196022471b7b |
13 | 98706185ba6 |
14 | 48614903779 |
15 | 2496c0097e2 |
hex | 135f7ca144f |
1331302110287 has 2 divisors, whose sum is σ = 1331302110288. Its totient is φ = 1331302110286.
The previous prime is 1331302110277. The next prime is 1331302110289. The reversal of 1331302110287 is 7820112031331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1331302110287 - 214 = 1331302093903 is a prime.
It is a super-2 number, since 2×13313021102872 (a number of 25 digits) contains 22 as substring.
Together with 1331302110289, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331302110289) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665651055143 + 665651055144.
It is an arithmetic number, because the mean of its divisors is an integer number (665651055144).
Almost surely, 21331302110287 is an apocalyptic number.
1331302110287 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331302110287 is an equidigital number, since it uses as much as digits as its factorization.
1331302110287 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 32.
The spelling of 1331302110287 in words is "one trillion, three hundred thirty-one billion, three hundred two million, one hundred ten thousand, two hundred eighty-seven".
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