1331334205040 has 80 divisors (see below), whose sum is σ = 3563366876352. Its totient is φ = 453125609472.

The previous prime is 1331334205027. The next prime is 1331334205051. The reversal of 1331334205040 is 405024331331.

It is a tau number, because it is divible by the number of its divisors (80).

It is a super-2 number, since 2×1331334205040² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1331334204994 and 1331334205012.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8599859 + ... + 8753298.

Almost surely, 2^{1331334205040} is an apocalyptic number.

1331334205040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1331334205040 is an abundant number, since it is smaller than the sum of its proper divisors (2232032671312).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1331334205040 is a wasteful number, since it uses less digits than its factorization.

1331334205040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17353314 (or 17353308 counting only the distinct ones).

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 1331334205040 its reverse (405024331331), we get a palindrome (1736358536371).

The spelling of 1331334205040 in words is "one trillion, three hundred thirty-one billion, three hundred thirty-four million, two hundred five thousand, forty".