1331400025130 has 64 divisors (see below), whose sum is σ = 2788019232768. Its totient is φ = 448339053120.

The previous prime is 1331400025079. The next prime is 1331400025147. The reversal of 1331400025130 is 315200041331.

It is a junction number, because it is equal to n+sod(n) for n = 1331400025096 and 1331400025105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 797819 + ... + 1816401.

It is an arithmetic number, because the mean of its divisors is an integer number (43562800512).

Almost surely, 2^{1331400025130} is an apocalyptic number.

1331400025130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1331400025130 is an abundant number, since it is smaller than the sum of its proper divisors (1456619207638).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1331400025130 is a wasteful number, since it uses less digits than its factorization.

1331400025130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1018931.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 1331400025130 its reverse (315200041331), we get a palindrome (1646600066461).

The spelling of 1331400025130 in words is "one trillion, three hundred thirty-one billion, four hundred million, twenty-five thousand, one hundred thirty".