Search a number
-
+
133201200000 = 273551110091
BaseRepresentation
bin111110000001101101…
…0010000001110000000
3110201211000120001110210
41330003122100032000
54140244001400000
6141105231554120
712423564342651
oct1740332201600
9421730501423
10133201200000
1151543672070
122199498b940
13c73a17360b
1466386c7528
1536e8dec350
hex1f03690380

133201200000 has 384 divisors, whose sum is σ = 482492868480. Its totient is φ = 32288000000.

The previous prime is 133201199921. The next prime is 133201200001. The reversal of 133201200000 is 2102331.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (384).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133201200001) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 13194955 + ... + 13205045.

It is an arithmetic number, because the mean of its divisors is an integer number (1256491845).

Almost surely, 2133201200000 is an apocalyptic number.

133201200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133201200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (241246434240).

133201200000 is an abundant number, since it is smaller than the sum of its proper divisors (349291668480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133201200000 is an equidigital number, since it uses as much as digits as its factorization.

133201200000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10144 (or 10112 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 12.

Adding to 133201200000 its reverse (2102331), we get a palindrome (133203302331).

The spelling of 133201200000 in words is "one hundred thirty-three billion, two hundred one million, two hundred thousand".