Base | Representation |
---|---|
bin | 11110010010011110100000… |
… | …011110110101001011001000 |
3 | 122110122212010211001021220112 |
4 | 132102132200132311023020 |
5 | 114430012314344401440 |
6 | 1151152200322013452 |
7 | 40026120213663152 |
oct | 3622364036651310 |
9 | 573585124037815 |
10 | 133211103122120 |
11 | 394995699a7091 |
12 | 12b35254aa7288 |
13 | 59439a37c64aa |
14 | 24c7647a0bad2 |
15 | 10601d6dc0965 |
hex | 7927a07b52c8 |
133211103122120 has 32 divisors (see below), whose sum is σ = 305380170369720. Its totient is φ = 52279074432000.
The previous prime is 133211103122093. The next prime is 133211103122147. The reversal of 133211103122120 is 21221301112331.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (133211103122093) and next prime (133211103122147).
It can be written as a sum of positive squares in 4 ways, for example, as 133027204522564 + 183898599556 = 11533742^2 + 428834^2 .
It is a super-3 number, since 3×1332111031221203 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31417710881 + ... + 31417715120.
Almost surely, 2133211103122120 is an apocalyptic number.
133211103122120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133211103122120 is an abundant number, since it is smaller than the sum of its proper divisors (172169067247600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133211103122120 is a wasteful number, since it uses less digits than its factorization.
133211103122120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62835426065 (or 62835426061 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 133211103122120 its reverse (21221301112331), we get a palindrome (154432404234451).
The spelling of 133211103122120 in words is "one hundred thirty-three trillion, two hundred eleven billion, one hundred three million, one hundred twenty-two thousand, one hundred twenty".
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