13321331201471 has 2 divisors, whose sum is σ = 13321331201472. Its totient is φ = 13321331201470.

The previous prime is 13321331201377. The next prime is 13321331201473. The reversal of 13321331201471 is 17410213312331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13321331201471 - 2¹⁰ = 13321331200447 is a prime.

It is a super-3 number, since 3×13321331201471³ (a number of 40 digits) contains 333 as substring.

Together with 13321331201473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13321331201473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660665600735 + 6660665600736.

It is an arithmetic number, because the mean of its divisors is an integer number (6660665600736).

Almost surely, 2^{13321331201471} is an apocalyptic number.

13321331201471 is a deficient number, since it is larger than the sum of its proper divisors (1).

13321331201471 is an equidigital number, since it uses as much as digits as its factorization.

13321331201471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9072, while the sum is 32.

The spelling of 13321331201471 in words is "thirteen trillion, three hundred twenty-one billion, three hundred thirty-one million, two hundred one thousand, four hundred seventy-one".