Base | Representation |
---|---|
bin | 1100000111011100010111… |
… | …0000000111110011010000 |
3 | 1202011120102212121000200220 |
4 | 3001313011300013303100 |
5 | 3221231434343430222 |
6 | 44200014132313040 |
7 | 2543324600523234 |
oct | 301670560076320 |
9 | 52146385530626 |
10 | 13322011311312 |
11 | 4276919098a70 |
12 | 15b1a8a772780 |
13 | 75834ca99692 |
14 | 340b086105c4 |
15 | 18180945ab5c |
hex | c1dc5c07cd0 |
13322011311312 has 160 divisors (see below), whose sum is σ = 37830835814400. Its totient is φ = 4006164687360.
The previous prime is 13322011311283. The next prime is 13322011311331. The reversal of 13322011311312 is 21311311022331.
It is a super-2 number, since 2×133220113113122 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 85438573 + ... + 85594355.
It is an arithmetic number, because the mean of its divisors is an integer number (236442723840).
Almost surely, 213322011311312 is an apocalyptic number.
13322011311312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13322011311312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18915417907200).
13322011311312 is an abundant number, since it is smaller than the sum of its proper divisors (24508824503088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13322011311312 is a wasteful number, since it uses less digits than its factorization.
13322011311312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 157041 (or 157035 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 13322011311312 its reverse (21311311022331), we get a palindrome (34633322333643).
The spelling of 13322011311312 in words is "thirteen trillion, three hundred twenty-two billion, eleven million, three hundred eleven thousand, three hundred twelve".
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