1332241104013 has 2 divisors, whose sum is σ = 1332241104014. Its totient is φ = 1332241104012.

The previous prime is 1332241104011. The next prime is 1332241104031. The reversal of 1332241104013 is 3104011422331.

Together with next prime (1332241104031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1106541997929 + 225699106084 = 1051923^2 + 475078^2 .

It is a cyclic number.

It is not a de Polignac number, because 1332241104013 - 2¹ = 1332241104011 is a prime.

Together with 1332241104011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1332241104011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666120552006 + 666120552007.

It is an arithmetic number, because the mean of its divisors is an integer number (666120552007).

Almost surely, 2^{1332241104013} is an apocalyptic number.

It is an amenable number.

1332241104013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332241104013 is an equidigital number, since it uses as much as digits as its factorization.

1332241104013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1332241104013 its reverse (3104011422331), we get a palindrome (4436252526344).

The spelling of 1332241104013 in words is "one trillion, three hundred thirty-two billion, two hundred forty-one million, one hundred four thousand, thirteen".