Base | Representation |
---|---|
bin | 10011011000111001111… |
… | …100110011001001101110 |
3 | 11201101012002102210102212 |
4 | 103120321330303021232 |
5 | 133312234444214410 |
6 | 2500033543250422 |
7 | 165156261664340 |
oct | 23307174631156 |
9 | 4641162383385 |
10 | 1332412101230 |
11 | 474088993611 |
12 | 196292149a12 |
13 | 98852124272 |
14 | 486bc0c3290 |
15 | 249d46b5b05 |
hex | 13639f3326e |
1332412101230 has 128 divisors (see below), whose sum is σ = 2866355251200. Its totient is φ = 436294688256.
The previous prime is 1332412101211. The next prime is 1332412101247. The reversal of 1332412101230 is 321012142331.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1332412101196 and 1332412101205.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 78152567 + ... + 78169613.
It is an arithmetic number, because the mean of its divisors is an integer number (22393400400).
Almost surely, 21332412101230 is an apocalyptic number.
1332412101230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1332412101230 is an abundant number, since it is smaller than the sum of its proper divisors (1533943149970).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1332412101230 is a wasteful number, since it uses less digits than its factorization.
1332412101230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17506.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 1332412101230 its reverse (321012142331), we get a palindrome (1653424243561).
The spelling of 1332412101230 in words is "one trillion, three hundred thirty-two billion, four hundred twelve million, one hundred one thousand, two hundred thirty".
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