Base | Representation |
---|---|
bin | 1100000111101001001001… |
… | …0010111110100011100000 |
3 | 1202011220022000220220100002 |
4 | 3001322102102332203200 |
5 | 3221311001402004134 |
6 | 44201342441315132 |
7 | 2543505620433143 |
oct | 301722222764340 |
9 | 52156260826302 |
10 | 13325443000544 |
11 | 427831a1a8974 |
12 | 15b2687a95aa8 |
13 | 758778a3931c |
14 | 340d522aa05a |
15 | 18195a87287e |
hex | c1e924be8e0 |
13325443000544 has 24 divisors (see below), whose sum is σ = 26239029579000. Its totient is φ = 6661562472576.
The previous prime is 13325443000543. The next prime is 13325443000553. The reversal of 13325443000544 is 44500034452331.
It is a junction number, because it is equal to n+sod(n) for n = 13325443000498 and 13325443000507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13325443000543) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36032774 + ... + 36400709.
It is an arithmetic number, because the mean of its divisors is an integer number (1093292899125).
Almost surely, 213325443000544 is an apocalyptic number.
It is an amenable number.
13325443000544 is a deficient number, since it is larger than the sum of its proper divisors (12913586578456).
13325443000544 is an equidigital number, since it uses as much as digits as its factorization.
13325443000544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72439242 (or 72439234 counting only the distinct ones).
The product of its (nonzero) digits is 345600, while the sum is 38.
Adding to 13325443000544 its reverse (44500034452331), we get a palindrome (57825477452875).
The spelling of 13325443000544 in words is "thirteen trillion, three hundred twenty-five billion, four hundred forty-three million, five hundred forty-four", and thus it is an aban number.
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